2 Parallel Plate Capacitor | Capacitor Class 12 | JEE Mains & Advanced

Watch Complete YouTube Lectures Distraction-Free Download the Competishun App 👉 https://play.google.com/store/apps/de... 🌐 Login for Courses & Test Series: 👉 https://i.competishun.com/ Popular Courses for IIT-JEE: Pratham | Prakhar | Prakhar Integrated I | Praveen | Pragyaan C3 | Champ | CATS | ABC | PYQ Express UTS | ATS 👉 Explore all: https://competishun.com/courses/ 📞 Support: 8888-0000-21 | 7410-900-901 | 7410-900-908 --------------- Topics covered in this Capacitor Class 12 lecture by ABJ sir IITD with timestamp: 00:00 - 02:30 What is a capacitor? : Two metals/conductors placed near each other is known as condenser/capacitor. This is an arrangement that stores charge, electric field and electrostatic potential energy. 02:30 - 12:15 Capacitance of capacitor & Energy stored: Formulae of the capacitance of the capacitor are explained by ABJ sir for metallic plates that are placed parallel to each other at some distance. ABJ sir also explains how to find the energy stored in any capacitor. 12:55 - 21:55 Parallel Plate Capacitor: Structure of Parallel Plate Capacitor & Formulae of Capacitance of Parallel Plate Capacitor for Different Mediums. 22:09 - 25:02 Important points about Parallel Plate Capacitor: Relationship of capacitance with Area of Plates & Separation b/w both plates. 25:25 - 29:49 Example on Parallel Plate Capacitor: In this example, we have two plates of same cross sectional area with charge +Q and -Q at a separation d. We have to find the electrostatics force b/w these plates. By this example ABJ sir explains derivation of the electrostatics force b/w plates. 30:02 - 36:25 Capacitor Problem 1: In this problem, We have parallel plate capacitor of capacitance C in gravity free space, and in equilibrium. One of the plate is hinged at mid point and another plate is connected with a spring of spring constant k. Separation b/w these plates is d & potential difference b/w both plates is V. So we have to find the extension in the spring. 36:45 - 44:18 Capacitor Problem 2 (Method 1): In this problem, We have a parallel plate capacitor of Charge Q in gravity free space. One of the plate is hinged at mid point and another plate is experiencing external force F in the opposite direction. Separation b/w these plates is d. Due to this external force, this separation becomes d+x from d. So we have to find (1) work done by the external agent (2) Change in potential energy stored in capacitor. 44:18 - 49:14 Capacitor Problem 2 (Method 2): In this problem, We have parallel plate capacitor of Charge Q in gravity free space. One of the plate is hinged at mid point and another plate is experiencing external force F in opposite direction. Separation b/w these plates is d. Due to this external force this separation becomes d+x from d. So we have to find the Change in potential energy stored in capacitor 49:59 - 57:25 Energy stored in Parallel plate capacitor in Different forms: ABJ sir derived different formulae of energy stored in Parallel plate capacitor Using different methods/concepts. 57:30 - 01:05:27 Capacitor Problem 3 : In this problem, We have two parallel plate of Charge 2Q and -Q, and capacitance of this system is C. Separation b/w these plates is d & Cross sectional area of the plates is A. We have to find the potential difference b/w plates.