Dinámica. Video 2. Cálculo diferencial aplicado a la cinemática de una partícula

Problem 11.2 The motion of a particle is defined by the relation: x = 12t³ − 18t² + 2t + 5, where x and t are expressed in meters and seconds, respectively. Determine the position and velocity of the particle when its acceleration is equal to zero. In this video, we solve a kinematics problem for a particle step by step. Starting with the position function: x(t) = 12t³ − 18t² + 2t + 5 we determine the position and velocity of the particle at the instant when its acceleration is equal to zero. During the procedure, you will learn to: ✅ Differentiate the position function to obtain the velocity. ✅ Differentiate the velocity to calculate the acceleration. ✅ Set the acceleration equal to zero and determine the time. ✅ Evaluate the position and velocity at the instant found. ✅ Interpret the results and their units. Results: 📌 Time: t = 0.5 s 📌 Position: x = 3 m 📌 Velocity: v = −7 m/s Subscribe to INGPASOAPASO to learn dynamics, statics, strength of materials, and structural design through step-by-step exercises. #Kinematics #Dynamics #Derivatives #Acceleration #Velocity #Position #CivilEngineering #INGPASOAPASO