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Learn how to become a professional, safe electrician capable of performing any electrical service: https://eletr.co/cortes-engehall/?utm... How to properly START a PUMP MOTOR using a STARTER SWITCH Starter switches are widely used to operate motors, especially pumps, safely and intuitively. The user only uses two buttons: on/off. This model is the LE1E0.5HP, which can operate motors from 0.5hp/220V, 1hp/380V, and 1.5hp/440V. It's worth noting that Schneider offers these switches to operate motors from 0.16 to 30hp, depending on your needs. The great advantage is that the switches come pre-assembled. Inside them, there's a contactor that starts the motor and a thermal relay that protects the motor against overload. One thing to note is that the electrical supply for this switch must have a circuit breaker. This circuit breaker will protect the entire control system, in this case the power wiring, contactor, and thermal relay. In short, the circuit breaker protects the starter switch. Since the switch is already assembled, simply power the phases at inputs L1/L2/L3. This way, the current will flow through the contactor, then through the relay, and then out to the load below the thermal relay at outputs T1/T2/T3. And if the motor is single-phase, how do I connect it? Well, one thing that can be very confusing is 220V phase/neutral or 220V phase/phase. There's really no mystery. If it's 220V phase and neutral, we power the phase at L1 and the neutral at L3. If it's 220V phase and phase, it's the same: one phase at L1 and the other at L3. And a good practice recommended even in the manual is to connect a jumper from output T3 to input L2 to ensure the contactor's lifespan, as this keeps all terminals energized. After that, simply connect the output to the load at terminals T1/T2. A very important detail is adjusting the motor current on the thermal relay. Let's say you're going to connect a single-phase pump with a current of 1.8A. In this case, you'll adjust this trimmer to just over 1.8A. I recommend 10% more, which gives approximately 2A. This way, protection in the event of a motor overload will be properly sized; if it exceeds this current, the relay will activate, protecting the motor.

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