Exercise 3.1 class 10 maths | Pair of linear equations in two variables class 10

Exercise 3.1 class 10 maths Class10Maths #NCERTSolutions #CBSEClass10 #MathsMadeEasy #ExamPreparation #LinearEquations #PairOfLinearEquations #Exercise3_1 #Class10Chapter3 #MathsExercise3_1 #StudyWithMe #MathsTutorial #MathsTricks #BoardExam2025 #MathsRevisionClass10Maths #Exercise3_1 #NCERTSolutions #LinearEquations #MathsMadeEasy #CBSEClass10 #ExamPreparation NCERT Solutions for Class 10 Maths Chapter 3 – Pair of Linear Equations in Two Variables Exercise 3.2 1. Form the pair of linear equations in the following problems, and find their solutions graphically. (i) 10 students of Class X took part in a Mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz. (ii) 5 pencils and 7 pens together cost 50, whereas 7 pencils and 5 pens together cost 46. Find the cost of one pencil and that of one pen. Solution: (i) Let there be x number of girls and y number of boys. As per the given question, the algebraic expression can be represented as follows. x +y = 10 x– y = 4 Now, for x+y = 10 or x = 10−y, the solutions are; Ncert solutions class 10 chapter 3-10 For x – y = 4 or x = 4 + y, the solutions are; From the graph, it can be seen that the given lines cross each other at point (7, 3). Therefore, there are 7 girls and 3 boys in the class. (ii) If 1 pencil costs Rs. x and 1 pen costs Rs. y. According to the question, the algebraic expression cab be represented as; 5x + 7y = 50 7x + 5y = 46 For, 5x + 7y = 50 or x = (50-7y)/5, the solutions are; (ii) x – y = 8, 3x – 3y = 16 (iii) 2x + y – 6 = 0, 4x – 2y – 4 = 0 (iv) 2x – 2y – 2 = 0, 4x – 4y – 5 = 0 Solutions: (i) Given, x + y = 5 and 2x + 2y = 10 (a1/a2) = 1/2 (b1/b2) = 1/2 (c1/c2) = 1/2 Since (a1/a2) = (b1/b2) = (c1/c2) ∴ The equations are coincident and they have infinite number of possible solutions. So, the equations are consistent. For, x + y = 5 or x = 5 – y 2. On comparing the ratios a1/a2 , b1/b2 , c1/c2, find out whether the lines representing the following pairs of linear equations intersect at a point, are parallel or coincident: (i) 5x – 4y + 8 = 0 7x + 6y – 9 = 0 (ii) 9x + 3y + 12 = 0 18x + 6y + 24 = 0 (iii) 6x – 3y + 10 = 0 2x – y + 9 = 0 Solutions: (i) Given expressions; 5x−4y+8 = 0 7x+6y−9 = 0 Comparing these equations with a1x+b1y+c1 = 0 And a2x+b2y+c2 = 0 We get, a1 = 5, b1 = -4, c1 = 8 a2 = 7, b2 = 6, c2 = -9 (a1/a2) = 5/7 (b1/b2) = -4/6 = -2/3 (c1/c2) = 8/-9 Since, (a1/a2) ≠ (b1/b2) So, the pairs of equations given in the question have a unique solution and the lines cross each other at exactly one point. (ii) Given expressions; 9x + 3y + 12 = 0 18x + 6y + 24 = 0 Comparing these equations with a1x+b1y+c1 = 0 And a2x+b2y+c2 = 0 We get, a1 = 9, b1 = 3, c1 = 12 a2 = 18, b2 = 6, c2 = 24 (a1/a2) = 9/18 = 1/2 (b1/b2) = 3/6 = 1/2 (c1/c2) = 12/24 = 1/2 Since (a1/a2) = (b1/b2) = (c1/c2) So, the pairs of equations given in the question have infinite possible solutions and the lines are coincident. (iii) Given Expressions; 6x – 3y + 10 = 0 2x – y + 9 = 0 Comparing these equations with a1x+b1y+c1 = 0 And a2x+b2y+c2 = 0 We get, a1 = 6, b1 = -3, c1 = 10 a2 = 2, b2 = -1, c2 = 9 (a1/a2) = 6/2 = 3/1 (b1/b2) = -3/-1 = 3/1 (c1/c2) = 10/9 Since (a1/a2) = (b1/b2) ≠ (c1/c2) So, the pairs of equations given in the question are parallel to each other and the lines never intersect each other at any point, and there is no possible solution for the given pair of equations 3. On comparing the ratio, (a1/a2) , (b1/b2) , (c1/c2), find out whether the following pair of linear equations are consistent, or inconsistent. (i) 3x + 2y = 5 ; 2x – 3y = 7 (ii) 2x – 3y = 8 ; 4x – 6y = 9 (iii)(3/2)x+(5/3)y = 7; 9x – 10y = 14 (iv) 5x – 3y = 11 ; – 10x + 6y = –22 (v)(4/3)x+2y = 8 ; 2x + 3y = 12 Solutions: (i) Given : 3x + 2y = 5 or 3x + 2y -5 = 0 and 2x – 3y = 7 or 2x – 3y -7 = 0 Comparing these equations with a1x+b1y+c1 = 0 And a2x+b2y+c2 = 0 We get, a1 = 3, b1 = 2, c1 = -5 a2 = 2, b2 = -3, c2 = -7 (a1/a2) = 3/2 (b1/b2) = 2/-3 (c1/c2) = -5/-7 = 5/7 Since, (a1/a2) ≠ (b1/b2) So, the given equations intersect each other at one point and they have only one possible solution. The equations are consistent. (ii) Given 2x – 3y = 8 and 4x – 6y = 9 Therefore, a1 = 2, b1 = -3, c1 = -8 a2 = 4, b2 = -6, c2 = -9 (a1/a2) = 2/4 = 1/2 (b1/b2) = -3/-6 = 1/2 (c1/c2) = -8/-9 = 8/9 Since , (a1/a2) = (b1/b2) ≠ (c1/c2) So, the equations are parallel to each other and they have no possible solution. Hence, the equations are inconsistent. (iii) Given (3/2)x + (5/3)y = 7 and 9x – 10y = 14