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💯 UNAM GUIDE · PHYSICS · TOPIC 3. WORK AND LAWS OF CONSERVATION 👇👇 EXTRA QUESTIONS BELOW 👇👇 ― UNAM Exam Frequently Asked Questions ― ► TOPIC 3. WORK AND LAWS OF CONSERVATION − Concept of mechanical work. − Concept of power. − Kinetic energy. − Potential energy. − Conservation of mechanical energy. − Conservation of momentum. − Collisions between particles in one dimension. − Dissipative processes (friction and rubbing). ► CONTENTS 00:00 Mechanical Work [Definition] 01:06 Mechanical Work [Example] 01:29 Mechanical Work [Example] 01:56 Power [Definition] 02:43 Power [Problem 1] 03:34 Power [Problem 2] 04:43 Power [Example] 05:11 Kinetic Energy [Definition] 06:49 Kinetic Energy [Formula] 07:09 Kinetic Energy [Formula] 08:09 Kinetic Energy [Definition] 08:39 Kinetic Energy and Temperature [Example] 09:04 Work-Energy Theorem [Definition] 10:03 Potential Energy [Definition] 10:58 Potential Energy [Example] 11:28 Energy Potential [Problem] 12:26 Mechanical Energy [Problem 1] 14:16 Mechanical Energy [Problem 2] 15:36 Mechanical Energy [Problem 3] 16:34 Mechanical Energy [Problem 4] 18:18 Collisions [Problem] 20:16 Friction [Definition] ✅ Study hard and take care of yourself ✌️ 👇👇 EXTRA QUESTIONS 👇👇 ►What is energy? R = The ability of an object to move. ►A body's ability to do work. R = Energy. ►A body with a mass of 5 kg falls from rest from a height of 20 m. How much kinetic and potential energy does the figure have at the beginning, middle, and end of the trajectory? Consider g = 10 m/s2. R = START: Ec = 0 J, Ep = 1000 J; MIDDLE: Ec = 500 J, Ep = 500 J; END: Ec = 1000 J, Ep = 0 J. [With the data given, we obtain the Ep at the beginning of the trajectory, and the Ec is zero because it begins with no speed. The rest is obtained by applying the principle of conservation of mechanical energy EM = KE + EP.] ►There are two skaters: one weighs 50 kg and is stationary; the other has a mass of 60 kg and is traveling at a speed of 4 m/s in the direction of the first skater. Determine the momentum before the collision. A) 200 kg/s B) 240 kg/s (CORRECT ANSWER) [m1*u1 + m2*u2 SUBSTITUTING 50*0 + 60*4 = 240] C) 290 kg/s D) 310 kg/s ►What effect does the force of air friction have on a falling body? A = A resistance to the body's motion. #UNAMGuide #UNAMExam #UNAM
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