PAU Física CV Junio 2026 | Problema 2B: Campo magnético resuelto paso a paso

In this video, we solve Problem 2B from the Physics section of the University Entrance Exams (PAU) in the Valencian Community from June 2026, corresponding to the magnetic field section. We work with two infinitely long, parallel, straight conductors carrying electric currents. Using the law of the magnetic field created by a conducting wire, we solve the three parts of the exercise step by step. 📌 In this video you will see: How to calculate the magnetic field created by a straight conductor. How to apply the right-hand rule. How to add magnetic fields using the superposition principle. How to calculate the magnetic force on a moving charge. How to apply the Lorentz force law. How to determine the magnitude, direction, and sense of the magnetic force. How to calculate the current intensity required to obtain a specific total magnetic field. Main results: The total magnetic field at point P is B = 1.5 × 10⁻⁵ i T. The magnetic force on the charge is F = 3 × 10⁻⁶ j N. The current in the second wire must flow upwards and its value is I₂ = 1.875 A. This exercise is very useful for reviewing magnetic fields, straight conductors, the right-hand rule, the cross product, the Lorentz force, and the superposition principle—fundamental Physics topics for the second year of high school and university entrance exams. 💙 If you'd like to support the channel: Bizum: 621007935 https://paypal.me/angelcuesta1972 📲 Follow me on social media:   / angel-cuesta-115048070199431     / profesorencasa1   👥 Become a channel member to access full videos and exclusive benefits:    / @angelcuesta