EN - 2017 - CÁLCULO - ÂNGULO ENTRE PLANOS π1 E π4

#navalschool #integral_calculus #differential_calculus The plane π1 passes through the intersection of the planes π2: x + 3y + 5z - 4 = 0 and π3: x - y - 2z + 17 = 0. Given that π1 is parallel to the y-axis, it can be stated that the angle that π1 makes with the plane π4: - 2x + 3y + z - 5 = 0 is: a) θ = arccos(9/√238) b) θ = arccos(-√157/9) c) θ = arccos(-9/√238) d) θ = arccos(√157/9) e) θ = arccos(√238/9)