EN - 2017 - CÁLCULO - |(|u + v |)|; y = ln(x² + x - 12); y = arctg(πx/2 - π)

#NavalSchool #Integral_Calculus #Differential_Calculus Consider the items below: I. The closed interval A is the smallest interval that contains all possible values ​​for |(|u + v |)|, with |(|u|)| = 3 and |(|v|)| = 4. II. The set B represents the domain of the function y = ln(x² + x - 12). III. The set C is given by the image of the function y = arctg(πx/2 - π). According to the information above, the set corresponding to ( A - B ) ∩ C is: a) {3} b) [1, π/2[ c) ]2, 3] d) [1,+∞[ e) ]1, 3[