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PROBLEM 5.73 The A-36 steel shaft has a diameter of 50 mm and is clamped at ends A and B. If subjected to momentum, determine the maximum shear stress in regions AC and CB of the shaft. 00:00 Applying the Sections Method ✅ The section method consists of making a cut at a distance x from the bezel A of the axis and at a distance x from the point C, where the torque of 300 N.m is applied. When making the cuts, remember that the reaction at support A is in the opposite direction to the torque applied at C, that is, clockwise. NOTE: when summing the moments for each shaft section, the internal torques AC and BC to be determined act counterclockwise by convention. Note that we are going to obtain the TAC and TBC torque as a function of the TA reaction. 04:35 Applying the Torsion Angle Formula ✅ Using the concept of torsional angle we know that the torsional angle of A with respect to B, that is, the torsional angle of one end of the shaft in relation to the other has to be equal to zero because the shaft is statically indeterminate . Therefore, it is known that because we have two sections on the shaft, the angle of twist that occurs in section AC plus the angle of twist that occurs in section CB is equal to zero. Therefore, by applying the torsional angle formula, we will obtain a third equation whose unknowns to be determined are TAC and TBC. This makes it possible to determine the values of the internal torque acting in the AC and BC region of the axis. 08:50 Calculation of Maximum Shear Stress ✅ Now, as we know the values of the internal torques, we apply the formula for the shear stress for each region of the shaft. 🔴 Complete your TWIST studies by clicking on this link here 👇 • Eixo Estaticamente Indeterminado | TENSÃO ... 📚 Source: Mechanics of Materials 7th Ed. (R.C. Hibbeler) *********************************************************** 🔴 RECOMMENDED playlist link (Twist): • TORÇÃO 📸 Follow me on INSTAGRAM: / engsteveroger

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