LeetCode 69: Sqrt(x) | Binary Search Explained Step by Step | Best Interview Approach 🔥

🚀 LeetCode 69 – Sqrt(x) | Binary Search Explained In this video, we'll solve LeetCode 69: Sqrt(x) using Binary Search with complete intuition, dry run, and interview-focused explanation. If you've ever wondered: 🤔 Why do we use Binary Search here? 🤔 Why do we search from 0 to x? 🤔 Why do we store the answer? 🤔 How do we avoid integer overflow? 🤔 Why do we move left or right after checking mid * mid? Then this video is for you! We'll understand the intuition first, perform a detailed dry run, analyze the time & space complexity, and finally code the optimized C++ solution step by step. 📌 Topics Covered Binary Search on Answer Intuition behind Sqrt(x) Dry Run with Examples Overflow Handling (long long) C++ Implementation Time Complexity & Space Complexity Interview Tips ⏱ Time Complexity O(log x) 💾 Space Complexity O(1) If this explanation helped you, don't forget to: 👍 Like the video 💬 Comment your doubts 📌 Subscribe for more DSA & Placement Preparation content! #LeetCode69 #Sqrt #BinarySearch #DSA #CodingInterview #CPP #LeetCode #PlacementPreparation #Algorithms #CompetitiveProgramming #TechInterview #Programming #DataStructures #InterviewPreparation #LetsCode