001 A LEVEL MECHANICS ITEM ACCORDING TO ASSESSMENT OBJECTIVES FULLY SOLVED

Master A-Level Mechanics with this detailed step-by-step solution for a common NCDC-style exam item. In this lesson, we solve two key problems: 1. Finding the magnitude and direction of the resultant force acting at corner A of a regular hexagonal display wheel with four forces (3N, 4N, 6N, and 2N). 2. Determining the horizontal force required on a 6kg box on a rough 45° inclined plane (μ = 0.5) — both the minimum force to prevent sliding down and the force needed to move it up with acceleration 2√2 m/s². Perfect for Senior 5 & Senior 6 students preparing for UACE exams. Clear force diagrams, resolution of vectors, and full calculations included. 🔔 Subscribe to TV Math for more O-Level, A-Level, and University Mathematics tutorials, revision sessions, and exam practice. Timestamps below 👇 00:00 - Introduction & Channel Welcome 01:07 - Understanding NCDC Assessment Objectives for Mechanics 02:44 - Full Question Breakdown (Hexagonal Wheel + Inclined Plane) 07:50 - Part A: Resultant Force at Corner A of Hexagon 08:37 - Drawing the Hexagon & Force Directions 14:15 - Resolving Forces into Components (Horizontal & Vertical) 19:05 - Calculating Resultant Vector Fx & Fy 21:18 - Magnitude of Resultant Force 23:38 - Direction of Resultant Force (Angle with Horizontal) 27:11 - Part B: Box on 45° Rough Inclined Plane 31:26 - Minimum Horizontal Force to Prevent Sliding Down 43:10 - Horizontal Force to Move Box Up with 2√2 m/s² Acceleration 54:29 - Final Summary & Exam Tips #ALevelMath #Mechanics #ResultantForce #InclinedPlane #UACE