CALCULUS | GRADIENT OF THE TANGENT TO A CURVE | K.C.S.E PAPER 121/1 | 2007 | QUESTION 5(re-done)
The gradient of the tangent to the curve y=ax^3+bx at the point (1,1) is -5. Find the values of a and b.
▶︎
Mid ordinate rule | KCSE 2015 | Question 13 | 121/1
▶︎
APPLICATION OF INTEGRATION KCSE 2021
▶︎
How to find Gradient at a Point on a Curve #gradientatapoint #gradientonquadraticgraph
▶︎
AREA APPROXIMATION | TRAPEZOIDAL & MID-ORDINATE RULE
▶︎
KCSE 2015 - CALCULUS - 10 MARKS - DIFFERENTIATION
▶︎
APPLICATION OF DIFFERENTIATION & INTEGRATION IN KINEMATICS
▶︎
Differentiation KCSE 2007
▶︎
Simon Cowell Was Skeptical... Then She Left Him Speechless | BGT 2026
▶︎
KCSE 2006 - INTEGRATION - AREA APPROXIMATIONS
▶︎
Why Aliens Would NEVER Invade Africa
▶︎
MATH: FORM4: DIFFERENTIATION: LESSON 8 (CURVE SKETCHING) (KCSE 2016 PP1 NO.23 & KCSE 2012 PP1 No.22)
▶︎
AREA APPROXIMATION | TRAPEZOIDAL RULE |AREA BY INTEGRATION
▶︎
CALCULUS (DIFFERENTIATION): TURNING POINTS OF A CURVE.
▶︎
ADHD Child vs. Non-ADHD Child Interview
▶︎
2021 KCSE MATHEMATICS PAPER 1 QUESTION 6
▶︎
DIFFERENTIATION | KCSE 2016 PAPER 2 | QUESTION 23
▶︎
The Most Polite Person EVER?!? | Family Feud Classics
▶︎
The Greatest Mathematician of Our Time
▶︎