The value of the integral: \(\int_{0}^{\pi/4} dx / \cos^4\)(x) is(1) 1/3(2) 2/3(3) 1(4) 4/3
🔥 Can you solve this *Definite Integration PYQ* in just **20 seconds**? 📌 *Question:* Find the value of [ \int_{0}^{\pi/4}\frac{dx}{\cos^4 x} ] 🎯 In this Shorts video, learn: ✔️ Definite Integration Shortcut ✔️ sec⁴x Integral Trick ✔️ Standard Calculus Formula ✔️ Fast NIMCET Solving Technique ✔️ Most Important Integration PYQ ✔️ Time-Saving Exam Strategy 💡 *Quick Answer:* [ \boxed{\frac{4}{3}} ] ✅ *Correct Option: (4)* 🚀 Daily PYQs, Maths Tricks, Mock Discussions & Last Minute Revision ke liye jude rahiye *Nitin Sir | INPS Classes* ke saath. 📲 Telegram Channel: [https://t.me/inps_01](https://t.me/inps_01) 📲 WhatsApp Group: [https://chat.whatsapp.com/EmreFjvCRhf...](https://chat.whatsapp.com/EmreFjvCRhf...) 🌐 Website: [www.inpsclasses.com](http://www.inpsclasses.com) 🌐 Online Portal: [www.inpsclasses.online](http://www.inpsclasses.online) 📸 Instagram: @inpsclasses1 📱 INPS Classes App: [https://play.google.com/store/apps/de...](https://play.google.com/store/apps/de...) 📞 Call/WhatsApp: 9838162263 #NIMCET2026 #Integration #Calculus #DefiniteIntegral #NIMCETMaths #INPSClasses #NitinSir #MathsShorts #MathsTricks #PYQ #MCAEntranceExam #CUETPG #MAHCETMCA #ExamPreparation #YTShorts #TrendingShorts #ShortTrick #IntegralQuestions
![If A = [1, 0, 0; 0, 1, 1; 0, -2, 4] and 6A^-1 = A^2 + cA + dI, where A^-1 is the inverse of A, I is](https://i.ytimg.com/vi/uglurATr8yA/hqdefault.jpg?sqp=-oaymwEjCNACELwBSFryq4qpAxUIARUAAAAAGAElAADIQj0AgKJDeAE=&rs=AOn4CLCKKhkN4nRE5TqO2pwvtoxGakbZYA)
If A = [1, 0, 0; 0, 1, 1; 0, -2, 4] and 6A^-1 = A^2 + cA + dI, where A^-1 is the inverse of A, I is
![The number of values of k for which the linear equations [NIMCET 2020]4x + ky + z = 0kx + 4y + z](https://i.ytimg.com/vi/FrHjq9P1jZk/hqdefault.jpg?sqp=-oaymwEjCNACELwBSFryq4qpAxUIARUAAAAAGAElAADIQj0AgKJDeAE=&rs=AOn4CLC13ekESffkcetHd9iu3M_rvtu9Fg)
The number of values of k for which the linear equations [NIMCET 2020]4x + ky + z = 0kx + 4y + z
The system of equationsalphax + y + z = alpha - 1x + alphay + z = alpha - 1x + y + alpha*z = alpha -
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