Reverse a Linked List | LeetCode 206 | Day 27 of DSA with Java

Welcome to Day 27 of 100 Days of DSA with Java. In this video, we solve one of the most important linked list interview problems: Reverse a Linked List. Instead of swapping or moving the nodes, we reverse the references between nodes. This is the key logic behind reversing a linked list efficiently. We will understand how to use three pointers: previous current next Using these pointers, we store the next node, reverse the current node’s reference, and then move forward until the entire linked list is reversed. Problem Covered: LeetCode 206 — Reverse Linked List Topics Covered: Linked List reversal Reversing references instead of nodes Previous, current, and next pointer logic Iterative approach to reverse linked list Handling empty linked list Handling single node linked list Java implementation Linked list interview problem LeetCode 206 explanation By the end of this video, you’ll clearly understand how linked list reversal works internally and how to solve LeetCode 206 using the iterative pointer approach. Hashtags: #dsa #java #linkedlists #ReverseLinkedList #DataStructures #codinginterview #placementpreparation