LeetCode Daily: 1833. Maximum Ice Cream Bars | Counting Sort Greedy Solution Explained.

🚀 In this video, we solve *LeetCode 1833 – Maximum Ice Cream Bars* using an optimized *Counting Sort + Greedy* approach. While sorting the costs array gives a straightforward solution, we can do even better by taking advantage of the problem constraints and using a frequency array to simulate sorting without actually sorting the input. 💡 What you'll learn: Why the problem is inherently greedy The intuition behind buying the cheapest ice cream bars first How Counting Sort works Using frequencies instead of sorting Optimizing time complexity with bounded values Step-by-step walkthrough of the complete solution 🧠 Key Insight: To maximize the number of ice cream bars purchased, we should always spend coins on the cheapest available bars first. Instead of sorting all costs, we count how many bars exist at each price and process prices in increasing order. This allows us to efficiently determine how many bars can be purchased at every cost level. We also discuss: Frequency Array construction Counting Sort intuition Greedy purchasing strategy Time Complexity: *O(N + M)* Space Complexity: *O(M)* where *M* is the maximum possible ice cream cost. This problem is a great example of: Greedy Algorithms Counting Sort Frequency Arrays Constraint-Based Optimization Interview Problem Solving If you're preparing for coding interviews, this is a great opportunity to learn when Counting Sort can outperform traditional sorting. 🔥 Subscribe for more LeetCode Daily solutions, coding interview preparation, DSA concepts, and contest editorials. #LeetCode #LeetCodeDaily #CountingSort #Greedy #FrequencyArray #Algorithms #DSA #CodingInterview #ProblemSolving #LeetCode1833