LeetCode 412 - Fizz Buzz Explained in C++ | Beginner Friendly Solution

In this video, we solve LeetCode Problem 412: Fizz Buzz using C++. We cover: Modulo Operator (%) Divisibility Checks Conditional Logic Step-by-step Dry Run Optimized O(n) Solution Time and Space Complexity Analysis Rules For each number from 1 to n: If divisible by 3, return "Fizz" If divisible by 5, return "Buzz" If divisible by both 3 and 5, return "FizzBuzz" Otherwise, return the number as a string Example Input: n = 15 Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"] Key Idea The most important condition is: if(i % 15 == 0) because numbers divisible by both 3 and 5 should produce: FizzBuzz After that: i % 3 == 0 gives: Fizz and: i % 5 == 0 gives: Buzz Otherwise, convert the number into a string and add it to the answer. Why This Problem Matters LeetCode 412 may look simple, but it tests: ✅ Conditional Logic ✅ Modulo Arithmetic ✅ Order of Conditions ✅ Basic Programming Fundamentals This is one of the most famous programming interview warm-up questions ever asked. Problem LeetCode 412 — Fizz Buzz Language Used C++ What You'll Learn ✅ Modulo Operator Usage ✅ Conditional Statements ✅ String Conversion ✅ Beginner Problem Solving If you enjoyed the video, make sure to: 👍 Like 💬 Comment 🚀 Subscribe More LeetCode videos coming daily 🚀 #leetcode #cpp #dsa #programming #cplusplus #codinginterview #leetcode412 #fizzbuzz #beginners #coding #algorithms #interviewprep