EX 6.1 Q 6 CLASS 9TH NEW COURSE | Arc Length & Area of Sector

In this video, we solve Exercise 6.1 Question 6 from the Arc Length and Area of Sector chapter with a complete step-by-step explanation. This lecture is designed according to the Punjab Curriculum & Textbook Board (PCTB) New Course 2026 syllabus. 📚 In This Video: Exercise 6.1 Question 6 Arc Length Area of Sector Complete Step-by-Step Solution Easy Method for Board Exams Class 9 Maths New Course 2026 Punjab Boards Preparation 🎯 Perfect for: Class 9 Students Punjab Boards 2026 School Exams Board Exam Preparation Self Study 00:00 - Introduction to Exercise 6.1, Question 6 and definitions of Arc Length and Sector of a Circle. 01:42 - Explanation of Central Angle ($\theta$) and the relationship between Radius and Arc Length. 02:44 - Formula for Arc Length ($L = r\theta$ or $s = r\theta$) and Area of Sector ($A = \frac{1}{2}r^2\theta$). 04:09 - Question 6 (Part i): Given values (Radius = 6 cm, $\theta = \frac{\pi}{3}$ radians). 04:37 - Calculating the Arc Length for Part (i). 05:29 - Calculating the Area of the Sector for Part (i). 07:18 - Question 6 (Part ii): Given values (Radius = $\frac{4.8}{\pi}$ cm, $\theta = \frac{5\pi}{6}$ radians). 07:35 - Calculating the Arc Length for Part (ii). 08:21 - Calculating the Area of the Sector for Part (ii) with step-by-step simplification. 11:41 - Final simplified result for the Area of the Sector in Part (ii). 👍 Like, Share & Subscribe to ALI ACADEMY for complete Class 9 Maths solutions. #Class9Maths #NewCourse2026 #Exercise61 #Q6 #ArcLength #AreaOfSector #PunjabBoard #PCTB #MathsSolution #BoardPreparation #AliAcademy #Class9