Rotting Oranges | Leetcode 994 Explained Simply (Multi-Source BFS) | NeetCode 150

Rotting Oranges Leetcode 994 Solution | Multi-Source BFS Explained | NeetCode 150 Binary Matrix Problem In this video, we solve Leetcode 994: Rotting Oranges using the optimal Multi-Source BFS approach. If you've ever been confused about when to use BFS instead of DFS, this problem is a perfect example. We'll build the intuition step by step, understand why one BFS level represents one minute, and implement the solution in C++. This is a very popular coding interview problem that teaches an important BFS pattern frequently asked in technical interviews. ⏱️ Timestamps 00:00 - Problem Understanding 00:50 - Quick Dry Run & Edge Case 05:06 - Example Walkthrough (Why BFS Works) 07:10 - Handling the Edge Case in Code 10:04 - BFS Setup (Queue & Fresh Count) 18:26 - Time & Space Complexity 18:50 - Interview Tip: Why Multi-Source BFS? 📚 What You'll Learn ✔ Multi-Source BFS intuition ✔ Why BFS is better than DFS here ✔ How BFS levels represent time ✔ Queue initialization strategy ✔ Fresh orange counting optimization ✔ Important interview insights ✔ Time & Space Complexity analysis ✔ Clean C++ implementation This problem is commonly asked in interviews at product-based companies and is an excellent introduction to Multi-Source BFS. If this video helped you, please like and subscribe to support the channel and help more developers learn DSA step by step. #Leetcode994 #RottingOranges #BFS #NeetCode150 #CodingInterview #DSA