Power of Four | LeetCode 342 Explained in C++ 🚀 | Easy Math Problem | Beginner Friendly

In this video, we solve LeetCode 342 - Power of Four using a simple and beginner-friendly C++ approach 😄 📌 Given an integer n, return true if it is a power of four. Otherwise, return false. A number is a power of four if it can be written as: n = 4^x where x is a non-negative integer. Example 1 Input: n = 16 Output: true Explanation: 4 × 4 = 16 or 4² = 16 ✅ Example 2 Input: n = 5 Output: false Explanation: 5 cannot be represented as a power of 4. ❌ Example 3 Input: n = 1 Output: true Explanation: 4⁰ = 1 ✅ What You'll Learn ✅ Math Logic ✅ Number Theory ✅ Loops and Conditions ✅ Division Operations ✅ Beginner-Friendly DSA ✅ LeetCode Easy Problems Approach 🔹 Check if the number is positive. 🔹 Keep dividing the number by 4 while it is divisible by 4. 🔹 If the final value becomes 1, then it is a Power of Four. 🔹 Otherwise, return false. Complexity Analysis ⏱ Time Complexity: O(log₄ n) 📦 Space Complexity: O(1) 🔥 Perfect for: ✔️ DSA Beginners ✔️ C++ Learners ✔️ LeetCode Practice ✔️ Coding Interview Preparation ✔️ Math-Based Problems 👍 If you found this video helpful, don't forget to Like, Share, and Subscribe! 💬 Comment your next LeetCode problem below. 🔔 Subscribe for more beginner-friendly DSA, C++, and LeetCode solutions. #leetcode #leetcode342 #poweroffour #cpp #cplusplus #dsa #coding #programming #algorithms #leetcodeeasy #mathproblem #interviewprep #computerscience 🚀🔥