Archimedes principle application | Solved problems - Kisembo Academy

This video is a continuation of application of archimedes principle series of solved problems. Kindly consider donating to help support the continued production of these videos by following this link https://dashboard.flutterwave.com/don... God Bless You transcript; we get to do some worked examples on this principle this first one calls a concrete block of mass 2.7 times 0:00:10.530,0:00:15.599 10 to the power 3 kilo grams and the 0:00:13.080,0:00:18.060 volume of that is totally immersed in 0:00:15.599,0:00:20.130 seawater of thus this density find the 0:00:18.060,0:00:21.449 weight of the block in air and drama to 0:00:20.130,0:00:23.090 the weight of the block and see what a 0:00:21.449,0:00:25.350 now let's first remind ourselves that 0:00:23.090,0:00:27.240 this should always be running at the 0:00:25.350,0:00:29.130 back of our minds but when we are 0:00:27.240,0:00:30.720 dealing with Asmodeus principle the 0:00:29.130,0:00:33.600 weight of the fluid that has been 0:00:30.720,0:00:38.280 displaced is equivalent to the up thrust 0:00:33.600,0:00:40.559 that that is X been experienced by that 0:00:38.280,0:00:44.850 body that has been sunk in the fluid 0:00:47.010,0:00:51.539 in air of course this is more 0:00:48.660,0:00:59.879 straightforward we know that weight is 0:00:51.539,0:01:01.440 given that by mass times gravity what is 0:00:59.879,0:01:03.899 the mass of this concrete block we are 0:01:01.440,0:01:07.530 talking about the mass is 2.7 times 10 0:01:03.899,0:01:09.330 to the power 3 so it's 2.7 times 10 to 0:01:07.530,0:01:12.810 the power 3 kilo grams multiplied that 0:01:09.330,0:01:18.930 by the gravity in all my videos i'll be 0:01:12.810,0:01:25.020 using gravity as 9.81 so this is going 0:01:18.930,0:01:30.780 to give us 2 point 6 4 8 7 multiply that 0:01:25.020,0:01:33.600 by 10 to the power 4 neutrons so that is 0:01:30.780,0:01:38.369 the weight of the block in air unless 0:01:33.600,0:01:40.829 otherwise stated in all my videos the 0:01:38.369,0:01:43.189 value fogey or the value for gravity 0:01:40.829,0:01:46.470 will always be nine point eight one 0:01:43.189,0:01:47.790 so that's Roman one answered so let's 0:01:46.470,0:01:51.119 look at what the weight of block in 0:01:47.790,0:01:56.189 Sawada is like so let's call this our 0:01:51.119,0:02:01.439 sea water we have this block in this sea 0:01:56.189,0:02:03.479 water of course now when this block is 0:02:01.439,0:02:06.450 in sea water it's experiencing enough 0:02:03.479,0:02:09.050 what kind of forces it experiencing it 0:02:06.450,0:02:12.060 is experiencing enough thrust force 0:02:09.050,0:02:14.010 let's call it that a thrust force 0:02:12.060,0:02:16.739 that is the force acting upwards then it 0:02:14.010,0:02:19.530 also has the force acting downwards and 0:02:16.739,0:02:23.280 this was acting downwards is the first 0:02:19.530,0:02:25.800 due to its weight so of course now that 0:02:23.280,0:02:28.530 it is intimidating deserving this force 0:02:25.800,0:02:31.050 do its weight acting downwards that is 0:02:28.530,0:02:33.660 the weight when it is in air acting 0:02:31.050,0:02:35.190 downwards versus its up thrust the first 0:02:33.660,0:02:37.470 post optimal it upwards 0:02:35.190,0:02:41.459 the difference between these two forces 0:02:37.470,0:02:44.190 is going to give us the weight of this 0:02:41.459,0:02:45.720 thing when it is in the fluid in other 0:02:44.190,0:02:48.420 words what I'm trying to say is that 0:02:45.720,0:02:51.150 when this thing before this block was 0:02:48.420,0:02:55.650 immersed in this fluid it was at first 0:02:51.150,0:02:58.080 dangling in air when it was in air its 0:02:55.650,0:03:02.190 weight is what just was acting downwards 0:02:58.080,0:03:04.860 its weight in air it was acting its way 0:03:02.190,0:03:07.349 it is just it's waiting air that was 0:03:04.860,0:03:11.849 pocketing downwards and upwards there 0:03:07.349,0:03:14.489 was no force then we get this this block 0:03:11.849,0:03:17.180 with its weight still acting downwards 0:03:14.489,0:03:19.910 then we come and dip it in water here 0:03:17.180,0:03:22.320 when we dip it in water here it 0:03:19.910,0:03:23.730 experiences now another upward force 0:03:22.320,0:03:25.739 acting on it so it means that this 0:03:23.730,0:03:28.260 upward force the up thrust force is 0:03:25.739,0:03:30.810 going to counter up some of this weight 0:03:28.260,0:03:34.019 acting downwards so when it counteracts 0:03:30.810,0:03:35.489 some of it it means that this block is 0:03:34.019,0:03:37.920 going to lose some weight 0:03:35.489,0:03:41.970 that is what we call the apparent loss 0:03:37.920,0:03:45.650 in weight of this solid now that 0:03:41.970,0:03:49.709 apparent loss in weight of that solid 0:03:45.650,0:03:52.530 means that this weight when it was in 0