Oxidation and Reduction reaction | Redox Reaction | KMnO4 and Oxalic Acid | Class 10
Electrochemistry Chapter No.16 In this video we will balance the reaction between potassium permanganate and oxalic acid in acidic medium using both oxidation number method and ion electron method We will identify which species is getting oxidized and which is getting reduced We will also explain the role of H2SO4 in the reaction and why acidic medium is required for KMnO4 to act as strong oxidizing agent The final balanced equation is 2 KMnO4 plus 5 H2C2O4 plus 3 H2SO4 gives K2SO4 plus 2 MnSO4 plus 10 CO2 plus 8 H2O You will learn how to find oxidation numbers assign change in oxidation state equalize electrons and balance H and O using H plus and H2O This example clears the concept of redox titration and is frequently asked in practical and numerical sections Watch till the end for tips to balance any redox reaction in acidic medium quickly Subscribe for more redox balancing and electrochemistry numericals Punjab Board New Syllabus subscribe my YouTube channel for more lectures @HusnainaMajeed

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