Symmetric Tree | LeetCode 101 Explained in C++ 🚀 | Recursion + Binary Tree | Beginner Friendly

In this video, we solve LeetCode 101 - Symmetric Tree using a simple and beginner-friendly Recursive Approach in C++ 😄 This is one of the most important Binary Tree problems for learning recursion and mirror tree concepts 🚀 📌 Problem Statement: Given the root of a binary tree, check whether the tree is symmetric around its center. A tree is symmetric if the left subtree is a mirror image of the right subtree. 💡 Example: 1 / \ 2 2 / \ / \ 3 4 4 3 Output: true Because the left side is a mirror of the right side ✅ 🔥 What You'll Learn: ✅ Binary Trees ✅ Recursion ✅ Mirror Tree Logic ✅ DFS Thinking ✅ Base Cases in Recursion ✅ Time & Space Complexity ✅ Beginner-Friendly Explanation 🧠 Approach: Compare left and right nodes. If both are NULL → return true. If one is NULL → return false. If values are different → return false. Recursively compare: Left Left with Right Right Left Right with Right Left If all comparisons match, the tree is symmetric 🚀 ⏱ Time Complexity: O(n) 📦 Space Complexity: O(h) where: n = number of nodes h = height of tree Perfect for: ✔️ DSA Beginners ✔️ C++ Learners ✔️ LeetCode Practice ✔️ Coding Interviews ✔️ Binary Tree Revision 👍 Like the video if it helped you. 💬 Comment your favorite Binary Tree problem. 🔔 Subscribe for more beginner-friendly DSA and LeetCode solutions. #leetcode #leetcode101 #symmetrictree #binarytree #recursion #cpp #dsa #codingforbeginners #programming #leetcodeeasy #cplusplus #algorithms #trees 🚀🌳