33 ATOMIC STRUCTURE | Probability distribution function | IIT advance | JEE main | chemistry

Watch Complete YouTube Lectures Distraction-Free Download the Competishun App 👉 https://play.google.com/store/apps/de... 🌐 Login for Courses & Test Series: 👉 https://i.competishun.com/ Popular Courses for IIT-JEE: Pratham | Prakhar | Prakhar Integrated I | Praveen | Pragyaan C3 | Champ | CATS | ABC | PYQ Express UTS | ATS 👉 Explore all: https://competishun.com/courses/ 📞 Support: 8888-0000-21 | 7410-900-901 | 7410-900-908 ---------------: 00:00 - 03:30 psi square (r,theta,phi)[ wave function]= psi r^2 x psi ^2(theta,phi).Sir has explained the meaning of all the terms in the equation 03:31 - 05:11 Radial probabilty distribution function 4 pie r^2 psi r^2 psi r^2=Radial probabilty density i.e. radial probability of finding electron per unit volume Radial probabilty of finding electron = psi r^2 x dv 05:12 - 11:31 Radial probabilty of finding electron in shell of thiclkness dr at a radia distance r =psi r^2 x Vshell.Sir has explained further with the help of diagram by first calculating the volume of shell.Radial probability of finding electron in a shell of thickness dr at a radial distance r =psi^24pier^2dr =4pie r^2 dr (radial distribution function)(or radial probability distribution function). 11:32 -12:40 Total radial probability of finding electron in a sphere of radius r= integrate the above expression from r=0, r =r 12:41 -16:30 To draw psi r vs r, psi^2 vs r ,4 pie r^2 psi ^2 vs r for various orbitals . These graphs are very important psi r= kr^ l x (a polynomial of r with degree n-l01) x e^r/k Radia wave fuction for any orbital ,Eg 1s orbital ,l=0 ,radial node=1-0-1=0 16:31- 21:15 Write the expression for 1s,2s , 3s ,2p , 3p ,3d and 4d.Graphs for 1 s : psi r=ke^-r/k' Infact for H-atom K'= ao =Bohr radius =h^2/4pie^2 mke^2=0.529 A 21:16 - 26:33 psi r=ke^-r/a0 Graph for psi r and r along with graph of psi r^2 and r .Graph of radial distribution function y=4pie r^2 psi r^2 ,peak represents maximum radial probability. 26:34 -32:30 For maximum radial probability distribution d/dr (4pie r^2 psi r^2 )=0 d/dr(kr^2 e^-2r/a0)=0 r^2 x e^-2r/a0 x (-2/a0) + e^-2r/s0 x 2r=0 -2r/ao =-2 rmax=a0 =h^2/ 4 pie^2 nke^2=0.529 A ,Distance from nucleus where probability of finding electron is maximum for H atom.This implies that results of Bohr model for H atom and outcome of quantum mechanical.Model are same .Bohr vmodel was pretty good for H and H- like species Best YouTube channel for JEE Main, Free JEE Main physics lectures, Best coaching for JEE Main and Advanced, JEE Main revision lectures free, Top quality IIT JEE preparation, IIT JEE full syllabus free lectures, JEE Advanced full syllabus crash course, Free coaching videos for IIT aspirants, Best online content for JEE aspirants, Free JEE coaching by IITians, Complete JEE course on YouTube, Free mock tests and revision for JEE, #JEEMain #JEEAdvanced #Competishun #inorganicchemistry #MohitTyagi #alksir