Exercise 10.2 Full Solutions | Tangents & Angles Of A Circle | Class 10 Math | Federal Board| NBF

Exercise 10.2 Full Solutions | Tangents & Angles Of A Circle | Class 10 Math | Federal Board | National Book Foundation #FederalBoard #ModelTownHumak #EducationalChannel #siranjumteaches #nationalbookfoundation This video covers Exercise 10.2 from Chapter 10 – Tangents and Angles of a Circle (Class 10 Mathematics, Federal Board, National Book Foundation). It includes full, step-by-step solutions to all questions with clear diagrams and explanations. The lecture covers tangents, central angles, inscribed angles, real-life geometry problems, and practical applications. Ideal for board exam preparation. 📘 Chapter: 10 – Tangents & Angles of a Circle 🧮 Exercise: 10.2 – Complete Solved 🏫 Board: Federal Board (FBISE) 📗 Book: National Book Foundation (NBF) 👨‍🏫 Teacher: Sir Anjum Teaches 📌 Don’t forget to Like, Share, and Subscribe for more helpful lectures. #Class10Math #Exercise10_2 #TangentsAndAngles #FederalBoardMath #NBFMath #CircleGeometry #SirAnjumTeaches #BoardExamPreparation #FBISE2025 #MathLecture 00:00:00 - Q1: Solve unknowns from given circle figure 00:09:00 - Q2: ∠BAO = 30°, find ∠ABO, ∠AOB, ∠ACB 00:15:21 - Q3: ∠BAC = 40°, ∠ACD = 60°, find ∠ABC, ∠BCA, ∠CAD 00:22:06 - Q4: AOB is equilateral triangle – find angles O and C 00:26:04 - Q5: AB ∥ CD, find angles AEB, ∠B, ∠C, ∠D 00:37:18 - Q6: BC is diameter, CD is tangent, x = 30° – find radius, ∠ABE, ∠ABC, ∠EBD 00:46:27 - Q7: ABCD square (10 cm), BOP → BCQ – find scale factor, CQ, ∠BQC, ∠BPO, AO, AR 00:57:03 - Q8: ∠QPR = 60° – find ∠QSR, ∠PRS, ∠PQS, ∠QTR, and explain acute angle 01:05:01 - Q9: ∠BPD = 130°, P is centre – find ∠BAD, ∠BCD, ∠ABC + ∠ADC 01:12:25 - Q10: PQ ∥ SR, ∠QPS = 95° – find ∠QRS, ∠PQR, ∠PSR 01:18:20 - Q11: ∠ADC = 120° – find ∠BAC and ∠CAD (AD = CD) 01:25:50 - Q12: ∠ABE = 95°, ∠BAE = 65° – find ∠ECD, ∠CDE, ∠CED 01:32:38 - Q13: Wall clock (radius 1 ft), string = 4 ft – find centre to nail distance and height above clock 01:36:09 - Q14: Wheel 99 cm from point A, centre to point A = 101 cm – find diameter and distance covered in 1 round