Застосування методу інтервалів до дробових нерівностей

It is shown how to solve fractional inequalities using the interval method 00:00 inequality: numerator (2x + 1)(x - 3) denominator (2 - x)(x - 5) less than 0 04:41 inequality: numerator x³(x - 1)^4(x + 5) denominator (x - 8)(1 - 4x) more than 0 09:51 inequality: numerator (x - 2)(x² - 1)(4x - 5 - 3x²) denominator x + 7 less than 0 16:31 inequality: numerator x² + 5x - 6 denominator (2 + x)(1 - 3x) less than 0 19:57 inequality containing the sum of fractions on the left side