Why averages in Warhammer 40k are sometimes misleading
For those curious: The probability distributions shown are binomial, B(7,p) and B(14,p), where p is the chance for a successful wound. I then simply transformed B(14,p) with x- k/2 since here each Paladin needs to take two hits, and voilá. Support me on Patreon: / hexfire Also follow me on IG: / hexfire.gaming #warhammer40k #warhammer #tabletopgaming
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