Let 𝑓:[−𝜋2,𝜋2] → ℝ be a continuous function such that 𝑓(0) = 1 and ∫ 𝑓(𝑡)𝑑𝑡 = 0𝜋03Then which of

Let 𝑓:[− 𝜋 2 , 𝜋 2 ] → ℝ be a continuous function such that 𝑓(0) = 1 and ∫ 𝑓(𝑡)𝑑𝑡 = 0 𝜋 0 3 Then which of the following statements is (are) TRUE ? (A) The equation 𝑓(𝑥) − 3 cos 3𝑥 = 0 has at least one solution in (0, 𝜋 3 ) (B) The equation 𝑓(𝑥) − 3 sin 3𝑥 = − 𝜋 6 has at least one solution in (0, 𝜋 3 ) (C) lim 𝑥→0 𝑥 ∫ 𝑓(𝑡)𝑑𝑡 𝑥 1 0 −𝑒 𝑥2 = −1 (D) lim 𝑥→0 sin 𝑥 ∫0 𝑥 𝑓(𝑡)𝑑𝑡 𝑥 2 = −1 #methodofdifferentiation #logderivative #higherorderderivatives #fundamentalofmathematicsII #FoM #Modulus #Inequations #Inequalities #continuity #TransformationofCurves #IrrationalEquations #functions #differentiability #AoD #conicsection #logarithm #fom #inequalities #quadratic #probability #JEEMains #trickymathsquestion #IITJEE #maths #calculus #khansir #bhannatmaths #MathsForIITJEE #JEEAdvancedMath #MathMadeEasy #JEEPrepMaths #CrackMathsJEE #IITMathsTips #MathsForEngineers #MathematicsSimplified #TopperMathTips #MathSuccessMantra #MasterAlgebra #AlgebraJEE #QuadraticEquationsJEE #BinomialTheoremTips #ProgressionsMadeEasy #JEEAdvancedAlgebra #SequencesAndSeries #CrackAlgebraJEE #AlgebraicConcepts #PolynomialMathTips #CalculusForJEE #DifferentiationConcepts #IntegrationMadeSimple #LimitsAndContinuityJEE #CrackCalculus #IntegralCalculusTips #DifferentialEquationsJEE #JEEAdvancedCalculus #RateOfChangeProblems #CalculusVisualization #TrigonometryJEE #MasterTrigonometricIdentities #AnglesAndGraphs #TrigonometricEquationsTips #LearnTrigFast #SineCosineRules #AdvancedTrigonometryJEE #CrackTrigConcepts #UnitCircleMaths #VisualizeTrigonometry #CoordinateGeometryJEE #MasterCirclesJEE #ConicSectionsTips #ParabolaSimplified #EllipseAndHyperbola #StraightLinesForJEE #AnalyticalGeometryTips #GeometryForJEEAspirants #FocusOnCoordinates #MathsWithDiagrams #ProbabilityForJEE #StatisticsMadeSimple #PermutationsAndCombinations #AdvancedProbabilityJEE #CrackProbabilityJEE #DataInterpretationMaths #ProbabilityTricks #JEEStatisticalConcepts #MathsWithLogic #RandomVariableJEE #VectorsForJEE #3DGeometryConcepts #PlanesAndLinesJEE #VectorSpaceMath #GeometryIn3D #MathsInDimensions #VectorMathMadeEasy #3DProblemsForJEE #MasterVectorJEE #MathsInSpace #MathsMockTests #PreviousYearMathsQuestions #SolveMathDaily #JEE2024Maths #MathsRevisionTime #SpeedAndAccuracyJEE #PracticeMathsProblems #MathExamTips #CrackJEEWithMaths #MathsPreparationJourney #MathsGrind #DreamBigWithMaths #SolveForSuccess #MathsJourney #KeepPracticingMaths #MathsToIIT #FocusOnMaths #StayConsistentWithMaths #NeverGiveUpMaths #SuccessInMaths #MathsStudyGroup #CollaborativeLearningMaths #DoubtClearingMaths #MathsLearningTogether #TopperTipsForMaths #LearnMathsOnline #MathsStudyPartner #PeerMathsLearning #AskMathsDoubts #SuccessWithMaths #MathsShortcuts #MentalMathsJEE #FormulaMastery #TrickToSolveMaths #VisualizeMathsConcepts #LogicalMathsThinking #TimeSavingMathsTips #TricksForIntegration #QuickMathSolutions #SolvingSmartly #DreamBigIIT #FutureEngineer #KeepPushing #SuccessMantra #NeverGiveUp #StudySmart #MotivationForJEE #BelieveInYourself #AchieveYourDreams #GrindForSuccess #SuccessJourney #HardWorkPaysOff #ConsistencyIsKey #YouCanDoIt #SuccessAwaits #ThinkBigAimBig #IITJEE #JEEMains #JEEAdvanced #EngineeringEntrance #JEEMotivation #IITPreparation #StudyForSuccess #JEEToppers #CrackJEE #JEETips #IITJEEPrep #EngineeringDreams #JEEPreparationTips #StudyEngineering #SuccessInJEE #TopEngineeringColleges #AspireForIIT #JEEQuestions #IITDreams #ExamTime #RoadToIIT #StudyGrind #JEETipsAndTricks #RevisionGoals #JEEPrepMadeEasy #EngineeringEntranceTips #FocusOnGoals #PrepareSmart #StudyEfficiently #ShortNotesForJEE #QuickRevision #LastMinutePrep #MockTestTips #CrackEngineering #VisualLearning #IITJourney #SuccessPathway #GrindHardForJEE #MasterYourConcepts #TopperTips #StudyRoutine #ExamStrategy #RevisionTime #EducationMatters #StudyTipsForJEE #LearningNeverStops #TopRankerTips #ExamReady #SolveAndSucceed #PreparationIsKey #CompetitiveExamTips #CrackItWithUs #ExamStrategies #MathForJEE #MathMadeSimple #CalculusTips #MathTricksForJEE #JEEAlgebra #SolveMathFast #ConceptualMath #CoordinateGeometry #MathPracticeForJEE #JEEAdvancedMath #JEE2024 #EngineeringEntrance2024 #CompetitiveExamReady #ExamWarrior #CrackEngineeringExams #JEEMains2024 #JEEAdvanced2024 #BoardAndJEEPrep #IntegratedPreparation #EngineeringAspirants Get Solutions to any Mathematics Question related to IIT JEE & JEE Mains Instagram: / ank_shbm Trending Tags: maths study tips study motivation how to study exam tips how to learn calculus Calculus how to get good grades jee advanced tips iit iit motivation Iit jee preparation how to study for exams Bhannat Maths Khan Sir iit bombay iit jee motivation tricky maths problem viral maths adda247 today live viral maths by navneet sir viral video youtube shorts khan sir comedy khan sir patna Khangsresearchcentre number series maths for bank exams viral maths adda247 live Beginner Advanced Intermediate Application of Derivative AoD

Let 𝜓1:[0, ∞) → ℝ, 𝜓2:[0, ∞) → ℝ, 𝑓:[0, ∞) → ℝ and 𝑔:[0, ∞) → ℝ be functions such that 𝑓(0) = 𝑔(0) =

Let 𝜓1:[0, ∞) → ℝ, 𝜓2:[0, ∞) → ℝ, 𝑓:[0, ∞) → ℝ and 𝑔:[0, ∞) → ℝ be functions such that 𝑓(0) = 𝑔(0) =

Let 𝑀 = {(𝑥, 𝑦) ∈ ℝ × ℝ ∶ 𝑥2 + 𝑦2 ≤ 𝑟2},where 𝑟 0. Consider the geometric progression 𝑎𝑛 =12𝑛−1,

Let 𝑀 = {(𝑥, 𝑦) ∈ ℝ × ℝ ∶ 𝑥2 + 𝑦2 ≤ 𝑟2},where 𝑟 0. Consider the geometric progression 𝑎𝑛 =12𝑛−1,

Graph of a continuous function has measure 0, Real Analysis 2

Graph of a continuous function has measure 0, Real Analysis 2

Let 𝑓1: (0, ∞) → ℝ and 𝑓2: (0, ∞) → ℝ be defined by 𝑓1(𝑥) = ∫∏(𝑡 − 𝑗)𝑗 𝑑𝑡, 𝑥 021𝑗=1𝑥0and 𝑓2(𝑥) =

Let 𝑓1: (0, ∞) → ℝ and 𝑓2: (0, ∞) → ℝ be defined by 𝑓1(𝑥) = ∫∏(𝑡 − 𝑗)𝑗 𝑑𝑡, 𝑥 021𝑗=1𝑥0and 𝑓2(𝑥) =

Let 𝑔𝑖:[𝜋8,38𝜋] → ℝ, 𝑖 = 1, 2, and 𝑓:[𝜋8,38𝜋] → ℝ be functions such that𝑔1(𝑥) = 1, 𝑔2(𝑥) = |4𝑥

Let 𝑔𝑖:[𝜋8,38𝜋] → ℝ, 𝑖 = 1, 2, and 𝑓:[𝜋8,38𝜋] → ℝ be functions such that𝑔1(𝑥) = 1, 𝑔2(𝑥) = |4𝑥

146. 17/11/2025 Yulia Zaitseva (HSE University, Russia)

146. 17/11/2025 Yulia Zaitseva (HSE University, Russia)

Let 𝐸 denote the parabola 𝑦2 = 8𝑥. Let 𝑃 = (−2, 4), and let 𝑄 and 𝑄′ be two distinct points on 𝐸.

Let 𝐸 denote the parabola 𝑦2 = 8𝑥. Let 𝑃 = (−2, 4), and let 𝑄 and 𝑄′ be two distinct points on 𝐸.

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