162. Find Peak Element | Binary Search Explained in C++ | LeetCode Solution

In this video, I solve LeetCode 162: Find Peak Element using the Binary Search approach in C++. ✅ Problem Explanation ✅ Optimized Approach ✅ Dry Run ✅ Time & Space Complexity ✅ Clean C++ Code Approach: We need to find an index where the element is greater than its neighbors. Using binary search, we compare `nums[mid]` with `nums[mid + 1]`. If `nums[mid] less than nums[mid + 1]`, peak lies on the right side Otherwise, peak lies on the left side or at `mid` Algorithm: 1. Handle edge cases 2. Initialize `low` and `high` 3. Find `mid` 4. Compare `nums[mid]` with `nums[mid + 1]` 5. Move towards the side where peak exists 6. Return the peak index Time Complexity: O(log N) Space Complexity: O(1) 🔗 GitHub: https://github.com/atulXdev 🔗 LeetCode Profile: https://leetcode.com/u/atul_singh_cg/ 🔗 LinkedIn:   / atul-singh-987b0b394   #leetcode #dsa #cpp #findpeakelement #binarysearch #arrays #codinginterview #striverdsa #leetcode162 #datastructures #algorithms