Senior 5 Mathematics: Designing a Wheelchair Ramp — Base, Height, Length & Angle Calculation

Watch all other items here:    • Senior Five Mathematics | New Curriculum S...   Senior 5 Mathematics: Designing a Wheelchair Ramp — Base, Height, Length & Angle Calculation Dive into Senior 5 Mathematics with TV MathHub. In this session, we solve a practical wheelchair ramp problem: a right-angled triangle side view with base x m, height y m, area 84 m², and safe inclination angle θ. Part 1: Prove x = 18(sec θ + tan θ)/3 and y = 28(sec θ - tan θ)/3 achieve the required area using trig identities. Part 2: If x + y = 31, determine base (x=24 m) and height (y=7 m) for optimal safety. Part 3: Calculate ramp length (hypotenuse=25 m) and angle θ ≈16.26°. Ideal for KCSE exam prep—master triangle areas, quadratic equations, Pythagoras, and inverse tan! New here? Subscribe for more Senior 5 math items, like & share. Check description for previous videos & playlist links. Chapters 0:00 Intro & welcome 0:05 Channel overview 0:18 Overview of today’s problem 0:47 Problem statement: ramp side view 1:18 Given requirements & tasks 2:04 Part A — proving area matches 84 m² 3:00 Using area formula (½ × base × height) 4:43 Simplifying base and height expressions 5:36 Area calculation conclusion 6:15 Part B — given X + Y = 31, find base and height 7:42 Deriving XY = 168 from area 8:45 Solving quadratic for Y 10:30 Finding corresponding X values 11:15 Choosing suitable X and Y for safe ramp 12:00 Base = 24 m, Height = 7 m 13:30 Part C — finding ramp length (hypotenuse) 15:04 Calculating hypotenuse → 25 m 15:59 Calculating ramp angle using tan⁻¹(7/24) 16:24 Angle of inclination ≈ 16.26° 17:14 Conclusion & closing remarks Get vidIQ to grow your channel faster! 🚀 https://vidiq.com/TVMATHSHUB