Proof: Derivative of sin(x) = cos(x) by First Principles

In this video, we prove that the derivative of sin(x) equals cos(x) by the very definition of the derivative, which is: df/dx = f'(x) = lim_(h approaches 0) f(x + h) - f(x) / h Thus: d/dx [sin(x)] = lim_(h approaches 0) sin(x + h) - sin(x) / h Thanks for watching. Please give me a "thumbs up" if you have found this video helpful. Please ask me a maths question by commenting below and I will try to help you in future videos. I would really appreciate any small donation which will help me to help more math students of the world. Please donate here: https://paypal.me/MasterWu Follow me on Twitter! twitter.com/MasterWuMath

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