Class 6 Maths | Ganita Prakash Chapter 5 Prime time | Page 126 Ques 4 to 7 Explanation

Class 6 Maths | Ganita Prakash Chapter 5 Prime time | Page 126 Ques 4 to 7 Explanation Figure it out 4. Find the remainders obtained when each of the following numbers are divided by a) 10, b) 5, c) 2. 78, 99, 173, 572, 980, 1111, 2345 5. The teacher asked if 14560 is divisible by all of 2, 4, 5, 8 and 10. Guna checked for divisibility of 14560 by only two of these numbers and then declared that it was also divisible by all of them. What could those two numbers be? 6. Which of the following numbers are divisible by all of 2, 4, 5, 8 and 10: 572, 2352, 5600, 6000, 77622160. 7. Write two numbers whose product is 10000. The two numbers should not have 0 as the units digit. Watch Full Chapter Solution:    • Prime Time Solutions | Class 6 Maths Chapt...   #class6maths #ganitaprakash #class6ncert #mathsbyshweta In this video: class 6 maths class 6 maths chapter 5 ganita prakash class 6 new mathematics book ganita prakash prime time in mathematics class 6 class 6 ganita prakash ncert maths class 6 chapter 5 ganit prakash class 6 chapter 5 class 6 class 6 maths chapter 5 prime time in mathematics ganitha prakash ncert class 6 maths chapter 5 class6 maths prime time maths class 6 ganit prakash class 6 maths ganita prakash syllabus class 6 maths textbook ganita prakash class 6th maths chapter 5 This video is for educational purpose only!! I do not support or promote copyright infringement. *FAIR USE* Copyright Disclaimer under section 107 of the Copyright Act 1976, allowance is made for “fair use” for purposes such as criticism, comment, news reporting, teaching, scholarship, education and research. Thank you for watching.