C₂H₄ Hybridisation, Shape & Bond Angle | Ethene sp² Hybridisation & Double Bond Explained

In this concept-packed video, we explore the hybridisation, molecular geometry, and bond angles of C₂H₄ (ethene) — a key alkene in organic chemistry. Learn how carbon atoms in ethene undergo sp² hybridisation and how the double bond is formed through orbital overlap. You’ll learn: 🔹 The electronic configuration of carbon in ethene 🔹 Formation of sp² hybrid orbitals 🔹 How one sigma and one pi bond form the C=C double bond 🔹 Why the geometry around each carbon is trigonal planar 🔹 Explanation of the 120° bond angle in C₂H₄ 🔹 Visualization of orbital overlap and the formation of π-bonds This video is ideal for: 📘 Class 11 and 12 Chemistry students 📘 JEE & NEET aspirants 📘 CBSE/ICSE/State board students 📘 Anyone studying chemical bonding, hybridisation, or alkenes We use concepts from valence bond theory and VSEPR theory to help you understand the flat, planar structure of ethene and the significance of the pi bond in its reactivity. Animated diagrams and clear explanations make it easy to visualize and remember. 📚 Topics Covered: sp² Hybridisation in ethene Sigma and pi bonds C=C double bond explanation Trigonal planar geometry Bond angles in organic molecules Comparison with sp³ hybridisation (ethane) ✅ Watch till the end for visual examples and MCQ-style questions to test your understanding! 🎯 Like, Comment, Share & Subscribe for more videos on core chemistry concepts and exam preparation tips. #C2H4 #Ethene #Hybridisation #sp2Hybridisation #ChemicalBonding #NEET #JEE #OrganicChemistry #Class11Chemistry