Concentration of a Solution in Titration Using Empirical Data | Titration Numerical | Grade 10

Concentration of a Solution in Titration Using Empirical Data | Titration Numerical | Grade 10 Chemistry | Quick Check 15.3 15.3 Titration Numerical Solved | Calculate Concentration of HCl using NaOH Class 10 Chemistry Learn how to calculate the concentration of a solution in titration using empirical data. This is Class 10 Chemistry Chapter 15 Stoichiometry, PTB Syllabus. Example 15.8: 15 cm³ of 0.5 mol/dm³ NaOH neutralizes 23 cm³ of HCl. Find concentration of HCl in mol/dm³. 📚 TIMESTAMPS: Titration Concept - Why we use NaOH vs HCl Step 1: Balanced Chemical Equation Step 2: Convert cm³ to dm³ Step 3: Find Moles of NaOH Used Step 4: Use Mole Ratio from Equation Step 5: Find Concentration of HCl Step 6: Final Answer + Exam Trick ✅ BALANCED EQUATION: NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l) Mole Ratio = 1:1 ✅ FINAL ANSWER: Concentration of HCl = 0.326 mol/dm³ 👉 SUBSCRIBE for Class 10 Chemistry Ch 15: @ChemWithSammer Board Exam Numericals in every day. ❓ COMMENT FOR ENGAGEMENT: Comment "326" if you got 0.326 mol/dm³ 👇 Comment "STUCK" if you got confused. #Titration #stoichiometry #Class10Chemistry #ChemistryNumericals #NaOH #HCl #Molarity #PTB #chemistryinurdu #BoardExam2026 #titration #numericals #class10chemistrychapter2 #calculate concentrationofhclnaoh #hcl titration