VUNESP 2026: Domine as questões que mais caem (em menos tempo).

Are you taking a public service exam with VUNESP in 2026? Then this math class for public service exams is for you! In this video, I solve questions in the style of the VUNESP exam board and teach techniques that help you find the correct answer much faster, saving time and increasing your chances of passing. You will learn practical strategies for interpreting statements, identifying mathematical shortcuts, and solving exercises from public service exams. In this lesson you will learn: Pythagorean triangles and the Pythagorean Theorem Perimeter and plane geometry First-degree equations Ratio and proportion Rule of three Pie chart Greatest Common Divisor (GCD) Techniques for solving math questions from the AVESP exam board Methods to save time on the test If you are studying for municipal, TJSP, PMSP, city council, or other VUNESP-organized public service exams, this content can make all the difference in your preparation. My goal is to show you not only how to solve the questions, but how to solve them faster than most candidates, using strategies that increase your performance during the exam. If this video helps you, please like, subscribe to the channel, and share it with other exam takers. Discover my complete courses: 🔗 Mastering VUNESP: Mathematics and Logical Reasoning https://cursos.profedutavares.com.br/... 🔗 Complete course for TJ-SP (São Paulo State Court) https://cursos.profedutavares.com.br/... 🔗 Course for Military Police Officer PMSP / Barro Branco (Military Police of São Paulo) https://cursos.profedutavares.com.br/... 🔗 Course for Military Police Soldier PMSP / Barro Branco (Military Police of São Paulo) https://cursos.profedutavares.com.br/... WhatsApp: https://wa.me/5514996585111 #PublicServiceExam #MathematicsForExams #vunesp #CommentedQuestions #Mathematics 00:00 - Introduction and the Professor's Mission Edu Tavares 01:04 - Question 1: Perimeter and Pythagorean Triangles (Golden Tip!) 06:17 - Question 2: Problems with Decimals and Interpretation 10:46 - Question 3: Ratio, Proportion and the "K" Technique 17:51 - Question 4: Pie Chart and Quick Rule of Three 22:04 - Question 5: GCD and Division into Envelopes (The Secret of Factorization) 25:51 - How to accelerate your approval in 2026 A flat rectangular plot of land, with a width and length measuring 200 m and 210 m, respectively, will need to have half of its area fenced off. To do this, it has been identified that one of the diagonals of the land can be used to divide the fenced-off area from the non-fenced-off area. Both parts, a and b, will therefore be triangular, and each of them will have a perimeter equal to According to the 2024/2025 Rainy Season Report, published by the Civil Defense of the State of Minas Gerais, the highest rainfall recorded in that State in January 2025 occurred in the city of Barbacena, while the highest rainfall recorded in February 2025 occurred in the city of São Lourenço. Combining the two rainfall amounts, there are 117.85 mm of rain, with Barbacena receiving 64.25 mm more rain than São Lourenço. Based on this information, it is correct to state that the number recorded in Barbacena in January 2025 was equal to According to information posted on October 2, 2023, on the Osasco City Hall's website regarding the Municipal Risk Reduction Plan, presented by the city's Civil Defense, a mapping of the city, carried out by the Geological Institute in partnership with the City Hall, identified 249 risk areas in the municipality, divided into risk of landslides, risk of erosion, and risk of flooding. Assuming that the risks are mutually exclusive, that is, each sector presents only one of the identified risks, if the ratio between the number of landslide risk sectors and the total number of risk sectors is 24/83 and the ratio between the number of sectors at risk of erosion and the total number of risk sectors is 4/83, then it is true that the number of sectors at risk of flooding identified in the aforementioned document will be equal to A pie chart was used to represent the number of "YES" and "NO" answers given during a survey in response to a single question. In the chart, the central angle corresponding to the 330 "YES" answers given to the question measures 220 degrees. Therefore, the total number of people who responded to the survey was equal to A donation collected 180 R$20.00 bills and 420 R$10.00 bills. All this donated money will be divided, for later distribution to needy families, into envelopes, each containing a quantity x of R$ 20.00 bills and a quantity y of R$ 10.00 bills, so that none is left over outside of an envelope. Assuming that the goal is to form the largest possible number of envelopes under these conditions, then each will contain a total value of