COMO DIVIDIR EM PARTES DIRETAMENTE E INVERSAMENTE PROPORCIONAIS - Prof Robson Liers

✔This video is part of a series of videos with basic math questions involving division into directly proportional parts and division into inversely proportional parts, a frequently asked topic in civil service exams. ✔Today we have two basic math problems: one is a civil service exam question about division into directly proportional parts and division into inversely proportional parts, and we also have a question that involves division into directly and inversely proportional parts simultaneously. Don't miss this lesson because it's a complicated question to interpret, and I'll show you two different ways to solve it. ✔One of the biggest challenges for students and civil service exam candidates is knowing how to interpret math problems. If this video helps you and you want the Mathematicamente com Prof. Robson Liers channel to continue growing, SUBSCRIBE, click "Like," and SHARE. ❤ If you want to support the channel through ⚠️ PicPay ⚠️ here's my profile: @robson.liers 🔴 VISIT OUR WEBSITE 🔴 http://www.mathematicamente.com.br 🔵 Video Questions 1) (Unicamp-SP) The amount of R$1,280.00 should be divided among three people. How much will each person receive if: a) the division is made into parts directly proportional to 8, 5, and 7? b) the division is made into parts inversely proportional to 5, 2, and 10? 2) Divide an inheritance of R$495,000.00 among three people in direct proportion to the number of children and inverse proportion to their ages. We know that the first person is 30 years old and has 2 children, the second person is 36 years old and has 3 children, and the third person is 48 years old and has 6 children. How much will each person receive? 📽 FOLLOW ME ON SOCIAL MEDIA 🎥 📲 YOUTUBE:    / mathematicamen.  . 📲 FACEBOOK:   / robsonliers.  . 📲 INSTAGRAM: (prof.robsonliers)   / prof.robson.  . 📲 SNAPCHAT: profrobsonliers 📲 Our website: http://www.mathematicamente.com.br 📲 EMAIL FOR PARTNERSHIPS: [email protected] 🔴 CHANNEL PLAYLISTS 🔴 ✅ HOW TO INTERPRET MATH PROBLEMS https://bit.ly/2RfMMPY ✅ FRACTIONS AND PERCENTAGES https://bit.ly/2FazWO5 ✅ SIMPLE AND COMPOUND RULE OF THREE https://bit.ly/2KMOPK8 ✅ EXAM QUESTIONS https://bit.ly/2Rg0qmj ✅ FIRST AND SECOND DEGREE EQUATIONS https://bit.ly/2IfmYk3 ✅ FIRST DEGREE EQUATION SYSTEM https://bit.ly/2MWP0oG ✅ NOTABLE PRODUCTS https://bit.ly/2X8W45z ✅ SIMPLE AND COMPOUND INTEREST https://bit.ly/2WAbxaE ✅ GCD AND GCD https://bit.ly/2MM0dbO ✅ MILITARY EXAMS (TESTS) https://bit.ly/2IewHXN ✅ FEDERAL INSTITUTES (TESTS) https://bit.ly/2KNDtFD ✅ PLANE GEOMETRY https://bit.ly/2RgzRxm ✅ TRIGONOMETRY https://bit.ly/2XJoosl NOW IT'S YOUR TURN! Divide the number 981 into parts directly proportional to 2, 6, and 3 and inversely proportional to 5, 9, and 4, respectively. SOLUTION: x = 2k/5 y = 6k/9 z = 3k/4 2k/5 + 6k/9 + 3k/4 = 981 K = 540 x = 2.540/5 x = 216 y = 6.540/9 y = 360 z = 3.540/4 z = 405 The terms are 216, 360, and 405, respectively #mathematics #proportionaldivision #proportion HOW TO DIVIDE INTO DIRECTLY AND INVERSELY PROPORTIONAL PARTS - Prof. Robson Liers