Math for fun, sin(z)=2

We know the range of sin(x) is between -1 and 1, inclusively, but that's just with real numbers x. What if our input for the sine function is a complex number? In fact, we can derive the complex definition of sine from the Euler's formula and we can write sin(z) in terms of complex exponential (e^(iz)-e^(-iz))/(2i) and we will be able to solve sin(z)=2. 💪 Support this channel,   / blackpenredpen   -ln(2+-sqrt(3)),    • small problem that i owe you from sin(?)=2   Euler's formula:    • Euler's Formula (but it's a speedrun)   *Sorry I forgot the square root. |z| =sqrt(a^2+b^2) **Also, I should have written the horizontal axis as "Re" and the vertical axis as "Im" ***The last time I did complex analysis was back in 2012